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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O
# S5 F2 E0 ?0 h) V! A; I
( I* f- I( D" l" i9 u3 |发现了一个有趣的现象，0 x. }$ Z N7 R7 N: f5 Q3 Y7 a
每一条大路，
2 ], L8 G% n, N' B: c按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f4 k8 B# J! G% L
按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z; |; L; Q, X/ r+ z" i0 v
按4珠路排列，有4种不同的路数0 x+ o2 d. S/ `+ P5 t3 @, s6 j
按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C
6 w2 m- _8 ]1 {$ [5 J- \) a什么意思呢，可能大家一时不清楚，4 ]% A" O+ }# S
我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l: }3 U$ R; R2 _
假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u J# N" `( Q2 C% Y4 o2 N v. u
12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h
7 z/ h9 \$ W E* P. e够极端了吧
7 l9 ^+ Y5 S/ u( y$ c0 I q5 c% s3 r( P2 Z按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F
4 `; J0 ^% A6 d% P如果我们去掉第一口，就会出现完全相反的结果：5 W6 z! ?/ J+ ?+ A* T
212121212121212121212121212121219 ^, G9 D0 J* ?2 w
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C
+ }% }2 Y) B- V9 f1 o如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O/ ^& r* i% d' b
所以每一条大路，! R6 V# q$ h. c; z% O" Y. l2 n+ s" A& s$ O ]
按2珠路排列，有2种不同的路数。7 I. J8 @, y+ \' O
再举一个列子：. g% d$ R& \4 Z7 H/ F3 e. g
大路：122122122122122122。。。- Q& ?1 x' o7 C6 R" r: W' [* L- w
按三珠路排列：, u G. F( s/ F P2 D7 {+ J. R
122，122，122，122，122，122。。。
7 p/ R: ?5 Q2 e0 @去掉第一口，变成：6 G2 V! \" L' c" k: d: E( W; Q, J4 W- K
221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M$ D1 T7 n# ] a- U; S c
去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W6 _' L7 G7 W {3 a3 f! ]
212，212，212，212，212，: y& l, B; I6 e- m. J# c) `
- N' }3 e2 I4 E4 |5 g去掉3口，又返回122，122，122，了8 B, z; d0 R- e! e+ p& a, g
所以每一条大路，
& K! C) D, G' S0 Z/ \按3珠路排列，有3种不同的路数。% x0 c, Y: ^) {9 `5 W
同理：按N珠路排列，有N种不同的路数。
8 P* G% I9 F. w! r我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O7 z- }* n- L+ G$ X" h/ g N8 _
字串83 L: R) G1 V- s2 Y+ Y
2 P1 }+ Z! R( d! t+ E5 w- p, d3 [6 U. s5 J' [0 {1 A" m' k( @2 U( j r; u3 i! z0 E
1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |
+ c, t$ X9 N; W2 e- e9 b, u2、为三多理论提供了下注的多面性奠定基础。) H5 k, e/ }; q5 A* L$ X# a; Q2 j6 i
3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.
$ g* g, v+ @3 n' c, G6 m! v |
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