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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O
6 v% n" B" _4 A) y
8 h& {2 g7 K b0 I; w发现了一个有趣的现象，
o) b* f; n4 f+ L4 t每一条大路，6 u6 ~9 G. y( m# G$ J% ^
按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f0 X, i7 ?# r# l) h: Q5 k
按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z
n* X, ]" U+ k7 g按4珠路排列，有4种不同的路数
+ k7 ^' x) \6 `$ y按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C( \/ J' ]; V Z9 g+ ^8 I
什么意思呢，可能大家一时不清楚，0 Y" D2 w) b: n8 N; P; M
我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l
4 y* Y; Z1 `4 v/ ]) x2 `- S假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u* ]. k: C4 ~ y; x2 l9 u2 Q
12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h
9 w, F2 O) ]& P, E) h9 B够极端了吧& Y3 l" r8 v$ P5 O9 c; \9 X1 n
按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F0 l# @7 m6 ]& N# D7 F
如果我们去掉第一口，就会出现完全相反的结果：- D: O' h+ r$ H" n0 u. j$ T, m
21212121212121212121212121212121
4 F4 N% v8 c6 U0 w1 q2 [% A3 D! D0 S变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C; t* ^- G7 t. N
如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O- i, F; d. L2 r$ j5 Z6 P+ `1 ?1 }2 v
所以每一条大路，! R6 V# q$ h. c; z% O
o+ Z1 d5 r4 ^/ _7 d) C按2珠路排列，有2种不同的路数。
( T. @( q; T/ Q0 T3 B再举一个列子：; I/ U0 i9 z* Z5 d5 @+ I
大路：122122122122122122。。。
% }5 \* f' m: h8 h' J. p按三珠路排列：
) s% [+ {6 x; A/ ^* Z' D k122，122，122，122，122，122。。。
+ s' ]* ~, M5 ^( R. |3 \去掉第一口，变成：6 G2 V! \" L' c" k: d$ ~7 T8 J- o' B9 ?, H
221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M6 C5 b: \1 m j
去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W
7 M1 ~1 v9 E+ {# h, N" e212，212，212，212，212，: y& l, B; I6 e- m. J# c) `, ?! t8 b# s0 o' _$ F
去掉3口，又返回122，122，122，了
; C1 B" R8 q$ b( y6 ?* I4 K所以每一条大路，
# J9 Q: ]) Q- q7 F+ W! B4 I7 t8 Y按3珠路排列，有3种不同的路数。
$ t Z/ Y* F' A2 N6 |同理：按N珠路排列，有N种不同的路数。
4 H- Y+ U; ]0 T( o' ]6 ~ }) v" T我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O7 z2 W5 c% S: p) U
字串83 L: R) G1 V- s2 Y+ Y: `* _' Y6 r, H' B. D l+ y; ]
- p, d3 [6 U. s5 J' [0 {1 A" m' k( @
, ` i f* H1 R7 N, [2 b1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |' i/ j& l! L& R7 s% \8 ^
2、为三多理论提供了下注的多面性奠定基础。- l3 v0 N. E0 D2 R
3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.
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