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& J& t. _0 M! r3 K$ I6 H- M9 H通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。! a# D4 R1 N: x2 G9 U
' W1 f, W( L8 ? 假设大路开这样的路:
! b7 X" ~5 u$ y* v! n! I2 i
# [. \9 U9 Q* w K$ ?8 [ 12121212121212121212121212121212。( @( a3 F" V7 y9 H3 F& l: e g$ N3 u6 |
n, i/ ?) S3 ]' G4 s- X
按2珠路,就是BPBPBPBPBP。2 R2 F8 S$ z' A. Y {1 z [
8 E0 L4 l3 x, L) `# M/ N
如果我们去掉第一口,就会出现完全相反的结果:; Q7 J4 |0 i* E {0 }; U
/ W+ e1 J4 _, m1 C 21212121212121212121212121212121。. u: Y& O( A) [- [* |
/ H" B; V- z+ C 变成了PBPBPBPBPB。# r5 R6 M0 `' x, E
9 S" v& o& c. l- C) d' S1 | 如果我们再去掉一口,又返回第一种情况了。$ H- Z8 Q+ Y0 r9 h+ }4 I
6 k* s$ M: w' I! L, @) P" B( F
所以每一条大路,按2珠路排列,有2种不同的路数。+ G; ?0 X h- g E8 u/ t7 @ {6 a
1 `/ o4 C6 m3 X5 I, \/ F 再举一个列子:
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大路:122122122122122122。
: Q. p9 V3 x6 n, i/ A' j8 f- U2 P- X( P% L( G
按三珠路排列:2 }( {, O* _6 W
: k6 a# G* `+ S5 p& a
122,122,122,122,122,122。, v, O; P# \ H' m
# @3 d* v X1 o
去掉第一口,变成:
- t% M! X1 L7 ~8 ^0 f! K2 b" G% \# _. d( \* @7 J+ p& A G1 D
221,221,221,221,221,去掉前2口,变成:5 {, ^3 L! O4 M, j7 q
6 q. c. ~0 Z/ D2 O' H
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。% {; b& X( H6 v
6 _. a/ x2 p. ~ `9 t 同理:按N珠路排列,有N种不同的路数。
; f J8 m1 h ^. O+ Y# I
% ?% `; U1 r8 q7 k; h' F" E4 E, W! u 我提出这个的意义在于:
+ J3 T2 V1 Z2 ^4 {5 l7 d* x) X3 |
@: H0 N1 { [8 r 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。7 K/ }( s( [. i5 H
, N8 O+ k2 ?% `
2、为三多理论提供了下注的多面性奠定基础。3 m o" h: A3 @# f
5 K% R- `9 z2 C- b" m* c: F 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
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