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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
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' @: K: |& P( C8 q+ U 假设大路开这样的路:* g3 g1 ?! D4 \" E1 ^
1 n0 U* ^! |" { j 12121212121212121212121212121212。 x( b& L X0 } ?
4 k1 L* N) S6 ~0 `' ~ C 按2珠路,就是BPBPBPBPBP。
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如果我们去掉第一口,就会出现完全相反的结果:) g/ T2 f, v- A X9 M
0 u \) L0 |, Q A9 z 21212121212121212121212121212121。# z& _5 {' h6 @# r7 }8 {/ T$ E8 t
d( w, R! H$ k+ h J* ^
变成了PBPBPBPBPB。5 ?2 h! K! _3 t
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如果我们再去掉一口,又返回第一种情况了。( ?- e8 s. x) f: [6 W7 I
6 @& f* d) E6 D& W/ K
所以每一条大路,按2珠路排列,有2种不同的路数。
& b: q b! P, a$ w. a
, v( \3 T) C+ C* `+ I+ x6 q 再举一个列子:
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( {6 j Q9 x4 m6 F* b 大路:122122122122122122。
% L4 ?) g$ r- |( O9 |6 w+ ~' [! u# ], S7 V' l
按三珠路排列:- o6 B% H0 X$ a# P
9 ?4 F: o5 k' y8 d6 D
122,122,122,122,122,122。
% P, p: V! W( d' D/ B; n
8 K4 c3 I; j# y 去掉第一口,变成:; J+ A" e- K4 d6 J
6 T; J3 l" w0 o7 Y' E, ^
221,221,221,221,221,去掉前2口,变成:1 D) n# {) {0 [2 h/ W# ]
( E% H ~" R( R0 [" ]" e 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。9 u* y% x5 _3 W5 Y
8 t/ ?% u% T- H# P
同理:按N珠路排列,有N种不同的路数。6 E5 k1 q/ B0 ]4 Y7 l
9 s& @# r; y* c; f6 N1 K6 N2 m 我提出这个的意义在于:7 O8 _' C8 l9 s5 Z; [
2 W" G! R5 y# C7 `3 }3 c0 D, H 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
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2、为三多理论提供了下注的多面性奠定基础。
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8 t8 @! r" q% b; Q 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。, N/ b- s4 E- ^/ x
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