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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。) ~& m5 [5 w5 l" j
~& I7 j4 v0 S- r) G 假设大路开这样的路:5 c) t* A3 A/ g n- C) n
4 j; {: h3 r" s2 v9 b 12121212121212121212121212121212。) b+ v' F" E6 ]% s! v
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按2珠路,就是BPBPBPBPBP。3 F4 e. X `/ R6 V" V, M7 a
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如果我们去掉第一口,就会出现完全相反的结果:
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* k# w% Q8 D. Z' F/ Q 21212121212121212121212121212121。
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& b( a5 J) C( U, K; t% h 变成了PBPBPBPBPB。5 n- ^, Z% Y" l- w N- D! t+ j
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如果我们再去掉一口,又返回第一种情况了。% y1 \* q- j8 J7 l
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所以每一条大路,按2珠路排列,有2种不同的路数。1 t0 G6 s1 l( \! K
# G4 L+ I) L# H, i6 J 再举一个列子:
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" x- q% D7 e# J9 t8 U0 y# F 大路:122122122122122122。
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按三珠路排列:& U1 w" Z! p! d0 p6 V' ^
# R3 K8 c! A" N( f& b3 m 122,122,122,122,122,122。
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6 Z2 F" p q, T {. O8 j$ ]' u: x 去掉第一口,变成:" ? a4 c h& s+ |; p
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221,221,221,221,221,去掉前2口,变成:
+ s7 S' V Y, ^6 y
- T: S" E2 z+ G2 ^8 f& a 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
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同理:按N珠路排列,有N种不同的路数。 f8 S# i5 T7 A8 X5 Z N: L1 j9 I
0 R6 p8 y, y# {! `' K& g; X 我提出这个的意义在于:
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t7 p/ M- A7 K: J, v 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
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2、为三多理论提供了下注的多面性奠定基础。 O% T$ j: g. x* `3 |4 R6 M
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3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
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