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/ f& w% r/ ^! [4 E, r% D6 h! g2 D通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。4 q/ ?5 F' R- i$ h. y
5 A( C8 }% [/ Q5 N) O
假设大路开这样的路:
- F+ d' d5 H3 l' k1 c" W5 n
* L3 i9 h) g* n& I: P0 Q L 12121212121212121212121212121212。
6 s+ p; f8 S0 k2 D3 h' a( f6 ]( P1 V# s. \. i8 M4 X- f
按2珠路,就是BPBPBPBPBP。
" k) i( C2 H6 U* b" q: @6 d3 {
8 `# B# n& I9 e/ ?" u 如果我们去掉第一口,就会出现完全相反的结果:4 J' \6 t$ D8 R; L! b; D
# h+ B, X0 K; Q" b, i5 @ 21212121212121212121212121212121。& W$ i& p. v, m" s6 Q8 J
7 v M& }; k C9 U% F! i7 v
变成了PBPBPBPBPB。$ P! ?4 H( ]$ p& ^6 M& ?2 E
8 }6 _8 V1 P) r: }
如果我们再去掉一口,又返回第一种情况了。
, u0 E/ j- L) T: {( A( S1 L6 I' I9 J! L' b: [1 c
所以每一条大路,按2珠路排列,有2种不同的路数。
t; s. Q* H! u+ Y q5 z8 @+ R& Z! \
再举一个列子:
$ [3 P8 B! D; H( `) P- Z6 E3 C2 W( u2 [6 |8 l5 I
大路:122122122122122122。3 A0 V8 h/ x3 n2 \
; k( Z w& Q: k8 h 按三珠路排列:' C7 K. K5 g# f# r9 k. l
* c+ A# z0 W) r O! `$ j9 u
122,122,122,122,122,122。
; y3 o ]* i6 x. E0 p
% h6 D8 P7 H$ s* |! x H; F% v 去掉第一口,变成:
! l! e; s; b$ R# z/ @ J4 f4 ]; A# I7 \
221,221,221,221,221,去掉前2口,变成:
& C W) M7 L$ `; K& O8 A% O$ x6 ^/ N
2 D& }, J+ {- @6 G; `& o- H# M 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
/ p3 C0 }, `- Z: O8 E- ~
7 ~/ _+ e' |$ ^% N4 v& Z 同理:按N珠路排列,有N种不同的路数。# I- u D6 u# {
. \* q3 @! x, X/ i( K$ z2 g' o# S 我提出这个的意义在于:- r5 v. p2 u2 c3 M
* u# [2 N& w4 s 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。5 E2 R3 R# F) E
+ d- v; Y+ t2 p
2、为三多理论提供了下注的多面性奠定基础。* p3 o! |7 Y! c3 Y( ]: x, |4 v
1 s' t- a" {; Z 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
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