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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
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假设大路开这样的路:
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- u$ `. q4 U2 y4 H9 v0 C' B6 r 12121212121212121212121212121212。
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2 s) i1 ^) ^3 k, }; C 按2珠路,就是BPBPBPBPBP。' X. v4 i, B& e' e2 P) U
% i( Y' M5 v- t4 d 如果我们去掉第一口,就会出现完全相反的结果:3 A- j8 g; E* H: u9 g5 k. |& x% N9 O
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21212121212121212121212121212121。- ~8 U9 Z r+ W0 M9 N
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变成了PBPBPBPBPB。
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如果我们再去掉一口,又返回第一种情况了。
6 E4 _8 v6 l4 e, ]7 D- o" j
8 C. U* l* v5 T2 a3 l 所以每一条大路,按2珠路排列,有2种不同的路数。; z- Z% u. t& L& K, [$ ?2 b
5 { Z% t: Y8 l! {7 u8 j& q 再举一个列子:' n7 Z7 S# v* }2 y% Y* i4 S7 D9 T2 F
$ A/ e/ J, R( F# d# T 大路:122122122122122122。
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按三珠路排列:
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122,122,122,122,122,122。
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去掉第一口,变成:+ }7 x6 M* C# u1 k6 O3 n' o
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221,221,221,221,221,去掉前2口,变成:& n4 {* f# X; H( x* |( @8 ^ v
, s2 V6 g% e: o0 L8 Z 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
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$ y( m e% x9 b: k8 ] 同理:按N珠路排列,有N种不同的路数。+ D) H, z+ v' J# \7 j
5 {& N) A2 J0 D; U 我提出这个的意义在于:
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1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。+ s( W& `6 ~+ c! {: \4 q8 \
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2、为三多理论提供了下注的多面性奠定基础。
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" W6 J% G& l0 l% I& q- O' [ 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
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