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[打法交流] 对百家乐珠路理论的一些拓展(转)
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1#
通过我几个月来对珠路理论的研究,
. n' z7 f( o: \4 c* }; G2 O- b0 H2 z7 w& m6 C
发现了一个有趣的现象,
  c$ E% a- y9 q每一条大路,
: v, U8 G$ k1 p* |按2珠路排列,有2种不同的路数8 G! o' j( {- o; [$ o! P1 C
按3主路排列,有3种不同的路数
( s/ }" F" P1 U  p: Q7 r/ I  j2 A$ T按4珠路排列,有4种不同的路数
# W: Z. J; {6 c; ]  {: u9 P1 R按N珠路排列,有N种不同的路数。
" ]9 ?1 K& i) |3 k+ u什么意思呢,可能大家一时不清楚,
/ l. p7 R5 q- Q3 |2 @( t: R+ ~6 n, [5 \我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。% q  r5 R$ A6 N1 K/ Z
假设大路开这样的路:- Z2 e; d6 ?7 R7 U. S1 f
12121212121212121212121212121212
5 V# N$ c5 {2 M' I0 c够极端了吧- C4 p6 ?+ n$ S# u# x4 G
按2珠路,就是BPBPBPBPBP.....
7 z% U9 |1 E, k6 |2 g如果我们去掉第一口,就会出现完全相反的结果:% Z. n( ~  c- [! k  C' H: ~9 I
21212121212121212121212121212121
4 M) J. w8 n7 Q5 i6 |/ B2 Y变成了PBPBPBPBPB.......
4 L7 k$ y2 I# h* K. X7 t( Q如果我们再去掉一口,又返回第一种情况了。3 D+ Y- f  l5 I) p& u  B6 ?  M) n
所以每一条大路,
9 c; Z$ S0 w. Q& k+ h' s按2珠路排列,有2种不同的路数。6 \' A/ O) m' e  {" g3 ^6 F5 _
再举一个列子:6 K- E" p0 S  [- @
大路:122122122122122122。。。4 |/ H0 _3 K2 m/ d& \) y& I6 L* ?
按三珠路排列:7 j  s: g5 s: F+ x$ }
122,122,122,122,122,122。。。( V1 k  [8 B/ Y% L
去掉第一口,变成:8 {) z* o" x. @! d4 M1 H) r
221,221,221,221,221,. \: z: {6 |; C" w$ |# b/ a
去掉前2口,变成:3 v  x; h' G8 K* S; B) ]4 Z* D
212,212,212,212,212,
  D" y- t# z' F$ V) ?+ {* Y) N去掉3口,又返回122,122,122,了
. f  F2 A- b6 L% ?/ Q所以每一条大路,/ P( ]* V& @# }0 p  X7 g
按3珠路排列,有3种不同的路数。
" z  H7 s, m% o- A: D同理:按N珠路排列,有N种不同的路数。, P0 y  v3 b& a7 c) l
我提出这个的意义在于:; u% _* z  F* E2 \/ v) ?: B
字串8
! W! Y) ~6 T( H" z2 W2 R0 P7 b1 H- X
1、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。  v: S4 J  ~; w4 {4 z
2、为三多理论提供了下注的多面性奠定基础。
6 E+ N9 y0 _/ V. ^# ^' q3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是 上上路.9 N1 N4 j: T0 i) I$ d, D

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avatar 天策-萌二姐 + 3 理论打法交流

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百家乐是可以研究路单的
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27#
跟着看看也是相当的行的啊。
avatar
厉害了,老司机懂得真多的感觉的啦!
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这个理论啊简直是非常给力
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24#
对于理论的东西实在不感兴趣
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这个是不是真的管用的了
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22#
也是要去学习下方法才行啦。
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21#
慢慢看,慢慢理解,需要一点领悟力
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20#
理论太深奥,也未必都能应用好的
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理论的东西,毕竟只是理论
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展的当然是要在看到的啊
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关于理论也是要看一下的了
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16#
理论虽然看起来很利害,但是我还是不行
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这样的理论打法是十分科学很有道理哦,我也来收藏
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楼主估计也是一个理论很内行的玩家,谢谢老哥的分享。
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我现在还是研究一下理论打法,感激楼主的分享,我也来学习
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