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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。! |8 Q% `1 U3 z( p) h; n" F* e
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假设大路开这样的路:, B1 m' s! W6 d- V6 K
( H( Z1 n. K5 C7 V+ Z 12121212121212121212121212121212。
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按2珠路,就是BPBPBPBPBP。% y+ y9 Z G+ {2 S8 n6 e: L
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如果我们去掉第一口,就会出现完全相反的结果:/ A: X7 a: z( N! ^6 v9 \
6 X9 A2 ?; n) L& M7 G 21212121212121212121212121212121。
9 o$ b8 K8 Y+ }
7 X6 d8 R. f& r/ h6 b7 w. t8 Q 变成了PBPBPBPBPB。% L$ K/ }3 d {* w( c% ~
. |/ o u/ z: G0 g5 H' X8 ]" [ 如果我们再去掉一口,又返回第一种情况了。
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所以每一条大路,按2珠路排列,有2种不同的路数。) W& d( b8 C$ A# }: A5 Q; B) u& W/ Y
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再举一个列子:
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大路:122122122122122122。& o5 g! j% C, v/ B; V( O, M5 i3 H
+ w- o3 m) P* o9 |- b- h0 T. O 按三珠路排列:, _( c, R, w, O
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122,122,122,122,122,122。
- i7 E, P/ t4 G5 p5 B- p6 f" f( {+ z+ n7 O! }
去掉第一口,变成:
, K' r5 o+ W8 `, b3 A7 b0 d B6 C# n
221,221,221,221,221,去掉前2口,变成:% e% y( l' d4 R2 z9 _
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212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
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8 G/ I2 T7 T) b) d, Q 同理:按N珠路排列,有N种不同的路数。$ o! V6 A! E# s. q/ g0 T5 F, |9 Z+ L
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我提出这个的意义在于:
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, v E# t" e1 C: q. y0 Y 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
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$ X' {. s6 f0 |2 ^. Y2 s 2、为三多理论提供了下注的多面性奠定基础。
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3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。: m; Z) r1 ?5 Q. a
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