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" G$ T$ I4 K: q# P; Z% k% x0 ~! L" o5 w8 S8 p( S. g
通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。0 O0 H! f# }$ f* f, B
9 V. `% U9 ~4 z% b$ w! o* B
假设大路开这样的路:! S5 K$ ?9 g( N* y* d2 j4 U
2 F, l7 ~& l+ D/ V! K: C
12121212121212121212121212121212。& k; R9 Y& I( `
$ W3 G! Z$ ~( r: W( R8 P5 G, M
按2珠路,就是BPBPBPBPBP。
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如果我们去掉第一口,就会出现完全相反的结果:
# f k; p2 G Y
! m1 @4 n' V5 w- K. N' y 21212121212121212121212121212121。
6 [$ M1 w$ Q- G- C9 b
: |3 e5 W1 p4 c2 e1 x/ O 变成了PBPBPBPBPB。9 s9 [! U% o* R
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如果我们再去掉一口,又返回第一种情况了。
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4 ]# X# v5 J3 }" y) [ 所以每一条大路,按2珠路排列,有2种不同的路数。
" [9 g" ^+ B" j& U% R. r" f8 s$ e+ a5 x% }$ x1 k
再举一个列子:2 S0 g6 |1 q& ?: V5 Q+ A/ |% @
) ` R% k' \1 D* p+ j q* \2 c0 O 大路:122122122122122122。4 S0 l, M6 S9 V: L4 F: K9 ~- F
. f& u+ @: q% \2 w2 t% J$ s& K7 D8 S 按三珠路排列:0 I; n# G3 [4 M% Z; X* l* H M
: S+ @4 }" k6 D& x 122,122,122,122,122,122。0 K% f! H8 K% O/ O4 R
4 K; L R, J+ h0 Y7 `1 W$ x. i7 t
去掉第一口,变成:8 ~* L. k% t. n) c
: o3 ]- t. k5 J$ {& _+ |" _" U 221,221,221,221,221,去掉前2口,变成:
# K! [ d! E4 a5 ~: z9 A5 Y/ [
! z9 h7 V5 V, m# L2 w 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。5 k, |8 E8 k6 w! r& d# b `# H- ~
- Y- j. X) [8 g( u 同理:按N珠路排列,有N种不同的路数。
( a( V5 z7 O" x: y. L% x* q( k% {; @2 j6 _# X4 e' [- g
我提出这个的意义在于:
& E; V# x# m$ y" a0 |, E: V8 z- G. F5 I. I% w
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
9 D/ w$ [6 o/ ~9 [" i5 b" b! p
8 q8 P6 z2 V+ s 2、为三多理论提供了下注的多面性奠定基础。/ W& L! Z" Z7 r' H( ^
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3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。) k/ x$ A$ e9 n4 K
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