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根据技术型彩民多年研究,得出以下几步大乐透的破解方法: . m# C0 M+ t9 {# P9 X% s/ }
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第一,前区号码初步判断,确定冷热号
1 z, Z6 r* g2 j2 [. ^$ M3 j( ~9 W' g7 |" _
根据前2-3期开出的号码,确定热号和冷号。比如前三期分别开出的号码为:
4 r! q K/ x) W7 g5 Q2 A2 c, W5 g& [; z! J5 S8 y
11 12 14 24 29 + 05 07 ' L5 [& m+ k# p' L
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10 12 20 21 25 + 06 09 01 2 ^! c3 `9 S3 l1 J* m4 O
9 u6 J+ O) t$ W+ @- O
12 23 28 35 + 02 05 2 u3 g% N' e) e$ S6 D9 b0 H
* N7 V+ K6 C2 E4 m7 _: r 我们可以看出12是最热号,3次都开出,01是最冷号,开出1次,而且没有周边号码(02、 03)开出。一般热好至少5期内容易继续开出,而且大乐透喜欢开出同尾的号码(比如12-22- 32)( Y+ @2 Z+ {; r
0 _! i) @0 q, d9 M3 U: j, v% J 第二,初步杀出前区号码 / ~( X* e. R3 k" q: S# X% F
8 W! b; K5 l( w' T 一般前1期的号码可以作为杀号的最好依据。我们可以认为只有1-2个号可能继续开出,所以 可以大胆杀掉3个号码。杀号可参考0 1 2路来进行判断,0路是指除3余0号码,1路则是除3余1,2 路除3余2。
% u- ?2 E1 z% f( j
! M6 F% Q4 F5 Q0 \ K 可见 1(1路) 12 (2路)23 (0路)28 (2路)35(2路) + 2 5 Y8 {4 |* ]5 [3 H4 W$ m
4 A7 c0 m2 ~: c* D& n+ u
其中 2路号最多,可以杀掉1个,因此杀掉 35,(上期杀热号)。 X4 _( z0 v6 m
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0路号这3期中比较冷,也可杀掉,因此杀掉 1,23(连3期杀冷号)。+ P8 U5 O8 x j& {/ O: f
' f+ _& Q0 `+ m$ | 以此类推,我们可以去掉1、23、35的1-35个号码中随机抽取4个(按照210路比例为1: 1:2)(杀掉的0路号最多,所以在比例上,0路号多一个)
0 _/ Z9 e0 u2 l5 f9 z0 y
: @9 h2 C6 S- x, Y 比如 选取 “8”“17”“19”“30”(过程中奇数偶数比例最好设为2:2)
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第三,确定前区号
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综合前两点,前区选号为 08 12 17 19 22 30,此时依据奇数偶数比例,随机杀掉一个(上 期的奇数偶数比是3:2),这次我们可以选择比例为2:3(倒置) ,所以杀掉一个奇数17,因此得 出前区最早选号为 8 12 19 22 30。
9 f' G/ }; d/ x1 v7 S+ w: W4 X1 K% S* w+ [6 r& |- O2 [$ b
以上三步确定红球方法,不止个位掌握与否
! G% L0 `" J9 C% X0 M: O" v; t: V5 f }& G; s4 y
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