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通过我几个月来对珠路理论的研究,/ i5 v# @$ S$ x$ ?9 w( G3 V. f5 Q
1 z0 p* ]3 r: ^7 k: \发现了一个有趣的现象,1 X+ U9 [; j" F; v3 S8 s8 g
每一条大路,
: h& V; U, @& E* e1 [4 z9 _按2珠路排列,有2种不同的路数
2 k! r( D; K, W, s. I按3主路排列,有3种不同的路数
9 g7 p9 T2 O. |9 [) X/ [' V按4珠路排列,有4种不同的路数# C3 {( X' C' N2 H+ W+ B
按N珠路排列,有N种不同的路数。
+ l4 z/ X4 [2 \什么意思呢,可能大家一时不清楚,
' w6 @; ^. n( F* E& \+ H- e2 [我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。+ S+ \6 M8 p/ f E& }
假设大路开这样的路:; s7 [% u( e3 O j
12121212121212121212121212121212
# B+ h, M9 o, T" D7 c够极端了吧
6 y4 U8 |3 Y' K5 Y( O6 v按2珠路,就是BPBPBPBPBP.....* C+ L: T: L. w$ c' X
如果我们去掉第一口,就会出现完全相反的结果:9 X; _9 H+ L+ N2 M8 d3 _
21212121212121212121212121212121
6 q5 O, H! S; h) i# s变成了PBPBPBPBPB.......% ?# Y1 u1 Z+ M$ f! V0 s: f
如果我们再去掉一口,又返回第一种情况了。
6 B6 U: a5 R2 P( Q" Y7 B2 i所以每一条大路,
: m# N3 g5 H6 ~, L C& t按2珠路排列,有2种不同的路数。0 y1 ]/ B4 y, D" p# k
再举一个列子:8 r( G; [. i U# m3 b+ M! t0 l1 o
大路:122122122122122122。。。
- _, @# m; A6 ~- t按三珠路排列:
% H2 n! a+ R' B: i$ Q$ Y& s122,122,122,122,122,122。。。' c" ?0 t" d- a5 {
去掉第一口,变成:& @, }3 @7 T2 o7 e* }
221,221,221,221,221,0 w5 l8 p$ _; `/ r" Y/ D
去掉前2口,变成:
) K- E+ y' h4 m! e212,212,212,212,212,- Y! e" |. p/ ~- j! d" j
去掉3口,又返回122,122,122,了
% W4 I$ o p/ [7 @ d: H1 }所以每一条大路, b! W: |7 J8 {! a
按3珠路排列,有3种不同的路数。, `! @7 K$ n' t1 W4 y
同理:按N珠路排列,有N种不同的路数。
+ ^' z. D+ j% I我提出这个的意义在于:: L! \) t0 g' z
字串8
' z4 a) C* Y+ g7 `7 p1 v+ @
' c* f% r) r: ~# w3 z) \; }1、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。9 l( U2 _3 ~. {" i$ |' A C0 g+ D" t% M
2、为三多理论提供了下注的多面性奠定基础。2 d) b5 o/ ^4 L" V8 K- Z
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是 上上路.
5 i4 L# S9 X6 r8 [+ D2 F9 c |
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你的理论打法不错的呀,赢钱了应该是打法对你有用哦~来收藏下了解下了 |
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我现在还是研究一下理论打法,感激楼主的分享,我也来学习 |
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楼主估计也是一个理论很内行的玩家,谢谢老哥的分享。 |
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