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通过我几个月来对珠路理论的研究,
3 `6 E3 D- x" e+ k, G1 p& E8 N- g# U; ^
发现了一个有趣的现象,
& H4 B1 }/ \$ i+ P. y; ^每一条大路,
% I, Y1 e8 }3 W9 S" A# |) U按2珠路排列,有2种不同的路数! D3 T7 z5 d- u9 M w) b% |
按3主路排列,有3种不同的路数
4 W$ k% o4 m9 H3 Q按4珠路排列,有4种不同的路数 d$ w" j V; x* p f. b4 x# p
按N珠路排列,有N种不同的路数。: L& k, X! ^2 Q
什么意思呢,可能大家一时不清楚,6 Y; X- i0 M5 D9 t' C/ p3 _
我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。& ~3 O! F: z/ V0 s4 L6 Z- b
假设大路开这样的路:
) U; B+ T, ?0 k) Z9 u4 _# f12121212121212121212121212121212" I" f' A- ^' b' f5 X# `. S. y8 e
够极端了吧; e7 ~& d1 H9 F( I' {/ x" q0 T% B
按2珠路,就是BPBPBPBPBP.....
# I4 w0 E- }3 @5 V如果我们去掉第一口,就会出现完全相反的结果:. O! ?3 Z- J* J4 j
21212121212121212121212121212121; K8 ]# |& K3 h
变成了PBPBPBPBPB.......
2 ]- p6 m7 W# r6 A7 P如果我们再去掉一口,又返回第一种情况了。
; ]: L) V6 l/ d+ g1 {所以每一条大路,- c' W! e1 ?! _) u
按2珠路排列,有2种不同的路数。( C3 d( k6 J3 }) p! G$ r0 w4 J
再举一个列子:1 m; Y3 [ r$ L% v! B5 B: G7 A
大路:122122122122122122。。。
3 v$ @; j* j9 P8 W& N按三珠路排列:
' _( j$ ?' }+ { w+ m- K5 X4 _122,122,122,122,122,122。。。. v7 Q A& q3 N* F) ?3 }! E8 F
去掉第一口,变成:
* [& W7 r% a: W9 Y1 K2 k221,221,221,221,221,
R3 I) G" e( }- y) @, s; o+ ]去掉前2口,变成:
+ B7 _" K& `- }# S& T1 [+ z212,212,212,212,212,
8 N4 K/ j+ f2 n去掉3口,又返回122,122,122,了2 o7 _* E1 a% Q/ j/ j8 R7 J% K
所以每一条大路,; t' l( C6 `. \* P6 @ o4 e- [
按3珠路排列,有3种不同的路数。
; i, H c8 O! q0 D同理:按N珠路排列,有N种不同的路数。$ |# L' }: [) Z, z& P1 t
我提出这个的意义在于:3 j! x( b r* m! G/ F
字串8
4 o& p9 ?1 B3 {6 T: f5 C/ `" r7 }( y2 X" V( u9 j# k# e, c
1、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。9 @" s0 F& W: O' h1 y# c- @3 _# W
2、为三多理论提供了下注的多面性奠定基础。
. X: X, p. B! R+ s6 @% r3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是 上上路.3 O( V4 K' ^$ r J
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你的理论打法不错的呀,赢钱了应该是打法对你有用哦~来收藏下了解下了 |
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我现在还是研究一下理论打法,感激楼主的分享,我也来学习 |
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楼主估计也是一个理论很内行的玩家,谢谢老哥的分享。 |
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