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[打法交流]
近期在网上研究到了个百家乐著名战术 蒙特卡洛战术
[复制链接]
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百家乐蒙特卡洛战术,需要纸和笔。但是不很难。* M8 C, k) l. n) s# o
5 O' y% M0 I: }8 U& ?6 a) }: E3 K" J(1) 首先写「 1 2 3 」的数列。: R- u E, d4 R E9 H* D( V: y- n
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(2) 赌本就是左端的数字 (1) 加右端的数字 (3) 即是 (4) 。
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* z4 F( }: b* [3 y: V0 w(3) 输了的话就在数列右端之外又加上顺序的下一个数,现在这个例子要加的数字 (=4) ->( 「 1 2 34 」 ) 。如此类推,并且重複上面的第 (2) 点 ( 但今次会是 (1)+(4)=5) 。
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. x* B- ^" Y7 _7 w7 V4 A' O& l# z! P& ?(4) 胜了的话,倍率 2 倍的游戏就把左端的数字 (1) 和右端的数字 (3) 消去。倍率 3 倍的游戏从数列上去掉左端的二个数字和右端的二个数字。- X1 N7 v( h& ?& F3 z5 f3 z
5 T6 r# r1 L- s1 M: ]! F1 o w& Y(5) 如果数列所有的数字都消了就代表结束。
5 F' k9 o5 K3 O2 U5 V! i/ b) J8 L7 }: s( j$ f" u0 e* K1 b
(6) 想继续的话,回到 (1) 。- |4 R' h, T0 h% l1 X6 X2 o, a1 r
. K: [6 {* Y) s/ a7 b; z- n8 @蒙特卡洛战术的问题,在于如果没有充分而源源不绝的赌金,就会出现途中被迫停止的可能。而且连败的话,亦有机会超越 Max Bet ( 赌注的上限额 ) 。# }9 @* _3 ]2 s
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二合一战术
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这个可说是蒙特卡洛战术的一种,是以 1 局取回 2 局所输的方法。方法简单。写下输了的金额,赌注就那个左端和右端的数字的共计金额。
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* T% Z' }# h5 L( {1 K& q) G譬如,先写下「 1 」。所以第一局的赌注是 1 。如这局输了,右侧添写 1 ,成为「 1 1 」。那个下一局赌注将会是左端和右端的共和 =2 。2 C8 ~- _( u( D, k
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反复这样做,如四连败,数列将成为「 1 1 2 3 」。因此下一赌注会是 4 ,而且胜了的话,消去左端和右端的数字,数列将成「 1 2 」,下一赌注就等于 1 和 2 的总数 3 。再胜的话,会变成?% V- x( o* d# [# f, v, e5 |
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儘管结果是 2 胜 4 败,共计收支是一加一减等于零。& h7 k: G Y3 d- R3 r6 f! Q
# \7 X. X" V# M6 X" X# A
这方法我试了不咋地,你们可能可以?* a- Z! q# l8 U6 {% V6 j
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