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[打法交流] 近期在网上研究到了个百家乐著名战术 蒙特卡洛战术
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1#
百家乐蒙特卡洛战术，需要纸和笔。但是不很难。
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8 O# V  u6 w8 s/ N3 a(1) 首先写「 1 2 3 」的数列。! v( b) r8 ]& m* r4 i" C8 C
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(2) 赌本就是左端的数字 (1) 加右端的数字 (3) 即是 (4) 。1 b  n4 q+ o* J, A9 a* g9 o4 F. j
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(3) 输了的话就在数列右端之外又加上顺序的下一个数，现在这个例子要加的数字 (=4) ->( 「 1 2 34 」 ) 。如此类推，并且重複上面的第 (2) 点 ( 但今次会是 (1)+(4)=5) 。: ]) g+ [& ]/ x8 e6 V
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(4) 胜了的话，倍率 2 倍的游戏就把左端的数字 (1) 和右端的数字 (3) 消去。倍率 3 倍的游戏从数列上去掉左端的二个数字和右端的二个数字。
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8 j) R4 _# C$ j5 b(5) 如果数列所有的数字都消了就代表结束。
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(6) 想继续的话，回到 (1) 。- n2 a  |. ?7 C8 A+ X; n# `
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蒙特卡洛战术的问题，在于如果没有充分而源源不绝的赌金，就会出现途中被迫停止的可能。而且连败的话，亦有机会超越 Max Bet ( 赌注的上限额 ) 。
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这个可说是蒙特卡洛战术的一种，是以 1 局取回 2 局所输的方法。方法简单。写下输了的金额，赌注就那个左端和右端的数字的共计金额。8 O. T$ @. P; P+ ^6 y
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譬如，先写下「 1 」。所以第一局的赌注是 1 。如这局输了，右侧添写 1 ，成为「 1 1 」。那个下一局赌注将会是左端和右端的共和 =2 。6 b9 t& F& R! u

' S$ i7 v3 X8 K  Y5 \# Q( |! {反复这样做，如四连败，数列将成为「 1 1 2 3 」。因此下一赌注会是 4 ，而且胜了的话，消去左端和右端的数字，数列将成「 1 2 」，下一赌注就等于 1 和 2 的总数 3 。再胜的话，会变成？$ h$ c& ]& z' q% E

4 Y1 g/ T& T2 g3 B儘管结果是 2 胜 4 败，共计收支是一加一减等于零。
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: f! u& q  h  W1 k) L$ u这方法我试了不咋地，你们可能可以?* N1 b$ x# i% z
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2#
百家乐玩家可以来了解一下哦

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3#
听着就复杂，谁研究出来的

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4#
这个战术也是来看看了解下的了啊

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5#
主题回复处广告图案-天策传媒
我不相信什么战术，我只相信自己的运气。

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6#
看到第三条时我就看不懂了啊

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7#
战术也是要看有没有用的呀

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8#
看来要认真学习了，学好了就有饭吃

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9#
战术方面已经好久没有碰过了啦

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10#
那也是要好好关注这方面的了

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11#
这战术也不是每个人都能用得上的吧

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12#
这个战术我以前也是听说过的

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13#
其实只要懂大数法则就不会信这东东

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14#
这个真的要仔细来研究下哦

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