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[打法交流]
近期在网上研究到了个百家乐著名战术 蒙特卡洛战术
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百家乐蒙特卡洛战术,需要纸和笔。但是不很难。) P7 w6 _% m; J, p5 m2 y
5 s' D6 Q4 R+ Z(1) 首先写「 1 2 3 」的数列。
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6 J( a5 w! ?; Q+ o, P7 o E(2) 赌本就是左端的数字 (1) 加右端的数字 (3) 即是 (4) 。
2 M$ D7 A5 p: H) E, l$ u' `0 n0 y* H3 m! s( r1 W* p0 Q9 @
(3) 输了的话就在数列右端之外又加上顺序的下一个数,现在这个例子要加的数字 (=4) ->( 「 1 2 34 」 ) 。如此类推,并且重複上面的第 (2) 点 ( 但今次会是 (1)+(4)=5) 。+ l3 W: s8 W" p' Q. p
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(4) 胜了的话,倍率 2 倍的游戏就把左端的数字 (1) 和右端的数字 (3) 消去。倍率 3 倍的游戏从数列上去掉左端的二个数字和右端的二个数字。
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(5) 如果数列所有的数字都消了就代表结束。
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9 }. m5 M0 T0 `# [+ t& B(6) 想继续的话,回到 (1) 。, X% u$ q8 _0 _2 L. f, G
" n- w, s7 T8 ?' l a蒙特卡洛战术的问题,在于如果没有充分而源源不绝的赌金,就会出现途中被迫停止的可能。而且连败的话,亦有机会超越 Max Bet ( 赌注的上限额 ) 。( q4 l9 D( @: o/ S9 G( g
8 g7 ]7 O8 L. n8 l
二合一战术
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j$ ]2 Q+ D" v: l' D这个可说是蒙特卡洛战术的一种,是以 1 局取回 2 局所输的方法。方法简单。写下输了的金额,赌注就那个左端和右端的数字的共计金额。8 C1 I) r0 {5 c, l9 W' d* y6 u Q
7 M9 b8 [# V8 `, R譬如,先写下「 1 」。所以第一局的赌注是 1 。如这局输了,右侧添写 1 ,成为「 1 1 」。那个下一局赌注将会是左端和右端的共和 =2 。; t' ~0 u+ n+ Q$ K
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反复这样做,如四连败,数列将成为「 1 1 2 3 」。因此下一赌注会是 4 ,而且胜了的话,消去左端和右端的数字,数列将成「 1 2 」,下一赌注就等于 1 和 2 的总数 3 。再胜的话,会变成? T( s6 L# K7 `7 U
, A$ M9 e! [' c9 A7 j儘管结果是 2 胜 4 败,共计收支是一加一减等于零。
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/ u9 s" P Y; m! Y这方法我试了不咋地,你们可能可以?
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