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眼里没有庄闲,只有连和跳,因为庄闲是一对一的,而连跳都是一对二的。理解也好不理解也好,这个讲起来费劲,就不过多讲解了,你只要记住百家le只有连跳没有庄闲就可以了,通常大家所看见的大路,第一行是满的,从第二行开始才有洞出现。
8 b; K+ U2 E- G1 P3 K, [9 G6 o# c/ z
4 ]5 T0 i2 V& k4 x( S 用什么办法把第二行也变满,让洞出现到第三行去呢?这就需要重新排列大路。一种全新的方式去排列大路(又是新用什么排列,用连,和,跳连就可以比如大路是(随机的)3 B# |$ f! R2 q& C6 L, R( s) p" M
: Q: }; r4 n! s5 _# J/ l. d3 z 第一行:OXOXOXOXOXOXOXOXOXOXOXOXOX(第一行永远是单跳)9 ~4 W. n, s: _# ^0 Y8 S) B
- E# Q, U9 k6 `4 T3 Z: ~" {! u
第二行:O X X O O OX O X (第二行开始出现洞)
& h! z. q2 {+ t, o7 I6 j, U
) B; O. z6 I* k& |; i& _' b; @ 第三行:O X O X X2 X2 O2 P( r) \& v) u- }* d
' ^) E6 c7 y+ n) O/ | 第四行:O X X
W# c% z* X; A8 Y" F2 Q5 q
, D8 W% ~- S# m M' _ 第五行: X, C% x# `* `+ U7 p; Y6 ]# n
$ t! q, d: z( K' _0 A3 E/ ]
那么新写出来的大路是怎么样的呢?
/ u1 P) s% P! L
4 _3 A5 R& S1 [, Y: N0 d 记住一个简单的口诀就可以写出新的大路:1.连是连;2.跳连也是连。3 C9 x3 M4 { j& M p2 ]
o" \$ k$ J- ^
如下(大家凑合着看吧,实在不行就自己拿笔抄一遍,和上面的路一一对应。)6 I+ a& Y$ u' t! Z
' z+ T. Q$ R: k5 @: i1 s$ M
第一行:OXXOXOXO OXOOX(第一行不再是单跳了)
. `6 O' }5 v( u& u+ [# k; L V3 A
% B$ `4 c2 |( C6 j- n 第二行:OOXXXOOX XXXXX (第二行也是全满的) q& T( W* x0 O% C' {( l$ {
- |9 Y |: y+ [& V0 f/ p: y( X0 ^9 e 第三行:OX OX XO XOOX (第三行才出现洞)
+ u# h& D U9 t9 F$ L& `2 G4 F. {/ I3 Q9 ^
第四行:O XO O XXX
8 _ P% R, A$ Z8 W! e- q5 y |+ @/ B
第五行: O
2 V4 |- g- A! _: Q
3 j* k/ }. a: ]& ~) ?! ] 通过以上排列,大家看见了,变换了组合方式以后,大路不再显的那么杂乱无章了。每一列要么是连,要么就是跳连。这就似乎是最初期的关系形态变化组合排列,通过这样的排列,从形态上看,整个路只有12个形态上的跳,其他全是连贯的(可能已经有人开窍了)。$ k ~' J+ B! A x6 c7 P$ L
; E' ?! b9 ]- K- m9 f. n
大家看第一行不再是完全的单跳,第二行没有洞的出现,第三行才开始出现洞,每一列最少是2个符号,通过这样的形态组合,实际上是减少了原本大路上的跳40%-60%,比如原来一靴牌60把,基本上是30个跳。30个左右连,而且是间隔无规律,杂乱无章的,按常规跳连的次数是基本一致的,周期越大,数字越接近。) O/ T! D+ _( f. X; F4 T1 a
) f4 V' k* C C. Z9 e+ ^" x 通过配列 可以把原本大路的跳精简到10-15个左右,相反增加了40-60%的连,以上是对大路形态转换的最初级形态,相信已经能对大家有帮助。至于怎么样去下单 ,一目了然了。* l% ^$ t% M" [ z2 K5 U# w) W4 w
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