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眼里没有庄闲,只有连和跳,因为庄闲是一对一的,而连跳都是一对二的。理解也好不理解也好,这个讲起来费劲,就不过多讲解了,你只要记住百家le只有连跳没有庄闲就可以了,通常大家所看见的大路,第一行是满的,从第二行开始才有洞出现。) N9 Y7 N$ J' N3 X3 [
6 ^8 L& H4 Y$ l3 j. _. |, j
用什么办法把第二行也变满,让洞出现到第三行去呢?这就需要重新排列大路。一种全新的方式去排列大路(又是新用什么排列,用连,和,跳连就可以比如大路是(随机的)
( W( l E" O. j% ~7 N/ B9 K# n& c3 r3 u. D0 \" t: F
第一行:OXOXOXOXOXOXOXOXOXOXOXOXOX(第一行永远是单跳)
- v) {0 f/ v; T) `1 \' h# Q# I c5 V9 k4 J- _7 {7 [% F
第二行:O X X O O OX O X (第二行开始出现洞)
' a! P2 k5 U8 y! U5 R9 R7 O; b G; ]' w! ~
第三行:O X O X X- d0 z( w' W& L
, m @( T; `) y* g7 X, o$ @
第四行:O X X
) F9 M2 Y" D1 C
# _ m$ Y* L& s 第五行: X
) f4 N3 P5 A, R; I3 G8 T0 {4 G! {- @4 Y7 P- `
那么新写出来的大路是怎么样的呢?8 K/ h' z4 A: C
+ f$ |0 a3 I: G$ O/ F) Q 记住一个简单的口诀就可以写出新的大路:1.连是连;2.跳连也是连。
& x2 a1 f$ G$ c- T7 L/ P/ C
2 c3 U* h- w" [ e 如下(大家凑合着看吧,实在不行就自己拿笔抄一遍,和上面的路一一对应。)
5 ]. ^7 H/ |& w$ t& p' k6 r# y l( d7 u2 _7 i7 b: f
第一行:OXXOXOXO OXOOX(第一行不再是单跳了)
+ P0 g1 ?( N. n7 {: W, a k2 P M1 I1 n
第二行:OOXXXOOX XXXXX (第二行也是全满的)
6 A+ l* j* p( F1 f! L( Z4 w" o8 x$ g' u- I/ ~* ]0 b7 t2 O( p* F
第三行:OX OX XO XOOX (第三行才出现洞), d3 A, q$ W; g
, v u) K! m. |4 f, z% R; @
第四行:O XO O XXX
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第五行: O7 V$ L1 m. k: H8 ]
4 }7 p5 c$ [6 {; c. q. i" C 通过以上排列,大家看见了,变换了组合方式以后,大路不再显的那么杂乱无章了。每一列要么是连,要么就是跳连。这就似乎是最初期的关系形态变化组合排列,通过这样的排列,从形态上看,整个路只有12个形态上的跳,其他全是连贯的(可能已经有人开窍了)。3 P+ T$ U n8 a& ~' S) M5 o# a3 C- L
' ]$ l5 b- m* W9 ?# ~* K 大家看第一行不再是完全的单跳,第二行没有洞的出现,第三行才开始出现洞,每一列最少是2个符号,通过这样的形态组合,实际上是减少了原本大路上的跳40%-60%,比如原来一靴牌60把,基本上是30个跳。30个左右连,而且是间隔无规律,杂乱无章的,按常规跳连的次数是基本一致的,周期越大,数字越接近。
2 X8 }" b1 s3 v. L' P% C) y2 I+ ?# ~9 v
通过配列 可以把原本大路的跳精简到10-15个左右,相反增加了40-60%的连,以上是对大路形态转换的最初级形态,相信已经能对大家有帮助。至于怎么样去下单 ,一目了然了。' O7 C3 h# b% \
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