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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
8 J* ]/ \/ z# u+ V: x: P# @# h) H0 a& m- r+ e1 B
假设大路开这样的路:# M' H- ~0 n5 L3 e# j2 |
" P' |. S3 K6 L) O" b 12121212121212121212121212121212。/ V0 S @$ u3 L9 G
& G+ u* T, ^7 u/ N
按2珠路,就是BPBPBPBPBP。' \. l: l- c3 N( _: k2 q$ C
1 H6 R# S7 {- v# ]3 l+ p
如果我们去掉第一口,就会出现完全相反的结果:8 r2 M( v. S+ T3 r
/ B$ i, [" i- [1 a
21212121212121212121212121212121。+ _+ ]2 \8 A# [" R7 B
, U+ P! ] D" I9 f+ Q' {; l 变成了PBPBPBPBPB。 U R4 E { E
" s! r0 q# }: J" Z- m
如果我们再去掉一口,又返回第一种情况了。. G+ n( X$ {% n/ l+ l( e( Y/ D
: p! a* L9 [9 O' y4 [# z! M% g
所以每一条大路,按2珠路排列,有2种不同的路数。! \( s1 q, P# N. {$ z: ~
, O* ^0 w3 H9 L3 V. A6 I8 q
再举一个列子:8 |$ J H8 l) n6 ?9 Y h
9 l+ p$ U) f! w. }1 i+ D 大路:122122122122122122。 j$ G/ z+ K) t! N# m! A3 T
2 q5 q+ |$ j# g/ b' Y
按三珠路排列:
/ u2 P# E* U6 S1 @9 G: q6 L& N8 X, w) i9 m0 C- v
122,122,122,122,122,122。/ `% a. z/ K, l, t
9 [5 H+ {1 \9 W3 {
去掉第一口,变成:
4 k9 `% |5 X& O, ^
6 C. C1 j. m/ }: l: i! _2 q 221,221,221,221,221,去掉前2口,变成:
' ^4 c8 H; c) v6 |
- }) P" }; n% F3 R 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。4 \: Q6 M: `% W. q5 w0 z
5 K/ l/ [' _# J) t# p/ ^
同理:按N珠路排列,有N种不同的路数。
' c+ w. u2 p8 B' l2 o' C$ v( l
! W4 ^: F, g* f# U9 }7 g 我提出这个的意义在于:
2 E$ I" f* v( _8 Q9 V2 |# ~" ^* R
& T- m' v# }! w, q5 F2 C 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。# n' h) P* s+ v7 q5 T1 b
! E5 O/ {) P9 t6 s- u
2、为三多理论提供了下注的多面性奠定基础。1 a7 Z( l# h9 e4 ?
. @+ ?7 _8 b: @! e7 b9 d) \
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。% T9 _: I/ |- h' a" c: B
; ^& y! L* ]4 F/ Q
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我现在还是研究一下理论打法,感谢你的分享,我也来学习 |
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