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[打法交流] 德州扑克手牌组合有多少种?(转载)
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1#
起手牌组合9 s2 e/ j( G( r' M! v
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德州扑克中可能的手牌组合数有C254=(54*53)/(2*1)=1326种特定的对子牌有C24=(4*3)/(2*1)=6种组合: ?: p( b* {; f
特定的非对子牌有4*4=16种组合
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特定的同花非对子牌有4*1=4种组合5 m" {" u: d) C' J0 ]  V. S; [

3 n# {! x3 P; d2 |# }. QAXs有13-1=12种组合
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KXs有13-2=11种组合) M# e4 i( r/ f) Z! H( r! O% n
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思考:去牌效应的应用。0 s! \$ j4 N- z2 k6 z# P" F: B" m5 Z
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HERO手上有一张A,那么对手AA的组合还有多少呢?- l0 ^. h- R6 Z0 n

# x, F' s4 k$ D1 B. s  }* |答:有C23=(3*2)/(2*1)=3种,与你没有A时的情况相比少了一半。
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& P8 c- U. S- }) Z5 L! \. {HERO手上有一张A,那么对手AK的组合还有多少呢?
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% ^! ~: u0 s( p8 {+ i答:有3*4=12种,与你没有A时的情况相比少了1/4。7 L6 v6 S2 |0 V/ B

$ Y- d3 y" ?( F! Y! \' i+ T( o手牌组合
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成牌组合
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FLOP没有公对时:
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3 X- Y6 ^& m6 q5 q! e) K$ T三条的组合有C23*C23=9种
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指定三条的组合有C23=3种* F' v$ c% i5 C8 f* {

; F, J6 C+ _* }- C' k两对的组合有C23*C23*C23=27种5 D  q- R; M; a/ n6 x1 F2 G4 K" [9 V

  f7 L/ m- ~- f1 I! @( v- _% i指定两对组合有C23*C23=9种' g3 q) t4 F+ t4 g' n
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TPTK的组合有3*4=12种9 U6 e6 H- h. T
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6 G, [/ S& U4 f& l- _# g. k+ r7 FFlop有公对时:+ Z! {) D" m- w' P' v' M
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明三条顶踢脚的组合有2*4=8种
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葫芦的组合有C23+C13*C12=9种
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听牌组合; |# g" q: i% A2 O. v

0 W6 z, `0 {' C* V2 JFLOP有两张同花时:, f% ~$ G# ~3 g$ ]2 d1 @/ D. G
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对手理论上的同花组合有C211=55种2 j$ t/ M- v4 K2 i+ F4 I
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而当你手上有一张同花时,对手理论上的同花组合有C210=45种
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% w* t: \. Z! W' U2 G+ ^在类似K34这样的FLOP时:
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( p- t+ M3 F  T6 C两头顺组合(25、56)有2*4*4=32种
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卡顺组合有(A2、26、57)3*4*4=48种3 j4 Z2 x' ~! d- S/ x

4 N8 a; L- B' |  H在类似K56这样的FLOP时:: ?/ r( O* L7 s8 N2 Y

, N" N/ F! n( X& h. p& d+ r* p两头顺组合有(34、47、78)3*4*4=48种
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6 D' R3 r6 A! w卡顺组合有(24、37、48、79)4*4*4=64种
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* G; o) ]& B- }/ k/ {5 O% c思考:当你知道对手只玩同花连牌时,组合数会发生怎样的变化呢?(这个请大家自己做个计算吧~)6 [0 w  u/ g+ U; x$ U* y

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2#
这个组合应该是很多的了啊。
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这个组合也是要看一下的了
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4#
知道有多少种,肯定是有好处的
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5#
主题回复处广告图案-天策传媒
你的理论打法不错的呀,赢钱了应该是打法对你有用哦~来收藏下了解下了
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6#
感谢楼主的理论分享,也是可以了解到好多的。
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理论实践得好,收米的时机就来了。
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你估计也是一个理论很内行的玩家,感激楼主的分享。
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9#
老哥的理论打法也是有在记录中的呀?
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10#
这个理论打法是需要向这个朋友多学习一下的。
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11#
基本理论也是要学学的了哦
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我的成果的功劳都是楼主像这样的理论分享。
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理论也许看着很牛逼,但是我还是不行
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这样的理论还是需要多多看看一下。
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这样的理论打法是十分科学好有道理哦,我也来收藏
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16#
老哥的理论打法还是很好啊,来收藏下了解下了
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理论看看一下,肯定都是不会吃亏的。
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