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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O
( e: c$ g+ H3 C4 w. Z2 \1 e( A' C' z# ?
发现了一个有趣的现象，
/ V/ |6 c- ?2 J( m每一条大路，- Q. y) \3 m% O1 y
按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f
: C4 k9 h# k& s; R: t1 q按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z
, i; r7 s2 O! d按4珠路排列，有4种不同的路数: f$ n$ U. @# Y8 J( q
按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C
: I1 j H2 C& n) W! b. ^/ _0 ], ^什么意思呢，可能大家一时不清楚，5 \0 M: c; d; F, o7 T* N
我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l
# \6 V' J, b% M4 x* y5 |8 b假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u9 ^5 M* W' f* O( k* x
12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h. L l8 V4 o' S* J
够极端了吧0 |, |: c- o* g) W
按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F
' o: ]0 r# j, L如果我们去掉第一口，就会出现完全相反的结果：
1 p" W: k/ G+ }% C& N: R6 R21212121212121212121212121212121$ M9 V2 k7 x$ Q8 f3 F% I$ T
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C
7 x- D N% q! j0 [ x7 p7 c% \, n8 j如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O
! O1 x' g8 s% Y+ q# S% ]所以每一条大路，! R6 V# q$ h. c; z% O
. o! t. ?% [& ^+ s% ~, \按2珠路排列，有2种不同的路数。
+ c2 |! E" j* C+ I! h, ?! j* w" T* s再举一个列子：
1 V# q# W2 Q3 ~大路：122122122122122122。。。
: k8 w2 G2 i. z) O* E0 g0 l按三珠路排列：$ Y+ z2 T- j. m
122，122，122，122，122，122。。。
9 U7 K+ P6 A$ L( x去掉第一口，变成：6 G2 V! \" L' c" k: d
* i5 r- G. Y" Y5 D2 w( Z% \3 p) d& G221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M$ b3 i) A+ l& f( J
去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W4 F7 N! @ J/ j) C% B
212，212，212，212，212，: y& l, B; I6 e- m. J# c) `
1 u q/ d& D6 e! q! z去掉3口，又返回122，122，122，了
5 e, X7 j( \- O# y8 D/ R8 m所以每一条大路，
0 A1 \4 z6 Q5 G按3珠路排列，有3种不同的路数。$ r5 k0 q8 d7 C9 W, T0 ?; H
同理：按N珠路排列，有N种不同的路数。% X! u' ?2 D' g. t2 C, c W7 {
我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O
1 a' ?# C/ e* n- w6 ]; \- E字串83 L: R) G1 V- s2 Y+ Y
; N. \: F7 m4 ]1 s. j+ u- p, d3 [6 U. s5 J' [0 {1 A" m' k( @
- v8 \0 m0 ?% i- i5 y/ {3 t1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |
( S0 `4 p& D0 c# y$ h2、为三多理论提供了下注的多面性奠定基础。
9 u6 R9 N2 r' x9 [/ Z# a0 A' X3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.9 j& e) t# N n6 V) `! o. A
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